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A test preparation claims that more than​ 50% of the students who take their test prep course improve their scores by at least 10 points. Instead of advertising the percentage of customers who improve by at least 10​ points, a manager suggests testing whether the mean score improves at all. For each customer they record the difference in score before and after taking the course ​(Afterminus​Before). ​a) State the null and alternative hypotheses. ​b) The​ P-value from the test is 0.65. Does this provide any evidence that their course​ works? ​c) From part​ b, what can you​ tell, if​ anything, about the mean difference in the sample​ scores? ​a) State the hypotheses.

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Answer:

If the mean score on a creativity test is 20, the standard deviation is 5, and the distribution is normal, the percentage of people who would obtain scores between 15 and 25 is a) 34% b) 14% + 34%= 48% c) 50% d) 34% + 34%= 68%

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hears my work

students in a class take a test and the mean score is 95 and the standard deviation is 8. If the lowest possible score to pass the test is 72, what percentage of students did not p Algebra -> Average -> SOLUTION: Students in a class take a test and the mean score is 95 and the standard deviation is 8.

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