Answer:
Molarity of Limonol is
M = 1.43mol/L
Step-by-step explanation:
M = mols/L
mols = g/molar mass
Therefore, determine molar mass, divide into grams luminol and divide that by 75 mL (in liters) to obtain molarity = M.
Molar mass of Limonol = 177.16 g/mol
mols = 19g / 177.16 g/mol
mols = 0.1072mol
Molarity of Limonol, M = 0.1072 mol / 0.075
M = 1.43mol/L