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A piston-cylinder device initially contains 0.3 kg of nitrogen gas at 160 kPa and 140oC. The nitrogen is now expanded isothermally to a pressure of 100 kPa. Determine the boundary work done during this process.

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Answer:

Work done by the gas is given as


W = 1.72 * 10^4 J

Step-by-step explanation:

As we know that the process is isothermal so here work done is given as


W = nRTln((P_1)/(P_2))

here we know that


n = (w)/(M)


n = (300)/(28) = 10.7 moles

now we have


W = 10.7 (8.31)(273 + 140) ln((160)/(100))

so we have


W = 1.72 * 10^4 J

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