The point L is plotted at A. (1, -1).
Explanation:
Step 1:
First, we plot the coordinates of both triangles.
The coordinates of the triangle EFG are as follows;
E = (-4, 4), F = (-4, -2), and G = (2, -2).
The coordinates of triangle JKL are;
J = (-2, 2), K = (-2, -1), and L = (x, y).
Step 2;
Next, we need to find the distances between at least two coordinates for both triangles.
The distances between vertical lines are found by calculating the difference in y values while for horizontal lines, the distances are found by calculating the difference between the x values.
The distance of EF

The distance of JK

The distance of FG

The distance of KL = (Scale factor)(the distance of FG),
The distance of KL

Step 3;
So the point L is 3 points away from point k on the x axis.
(x, y) = (-2+3, 1) = (1, -1).
So point L is plotted at option A. (1, -1).