Question

What is the equation, in slope-intercept form, of the line that is perpendicular to the line

y-4= (x-6) and passes through the point (-2,-2)?

A) y=-2/3x-10/3
B) y=-2/3x+10/3
C) y=3/2x-1
B) y=3/2x+1

Answer 1

y = -x - 4

Explanation:

Compare the given y-4= +1(x-6) to y - k = m(x - h), where (h, k) is a point on that line. We then know immediately that the slope of the given line is -1/1, or m = -1.

A line perpendicular to this given line that also passes through (-2, -2) is then:

y + 2 = -1(x + 2), or y + 2 = -x - 2, or y = -x - 4

Answer 2

c is the closest to point (-2,-2)

Explanation: