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A sample of propane occupies 274 L at 133 kPa and 316K. Find its volume at 98 kPa and 616K.

1 Answer

2 votes

Answer:

725L

Step-by-step explanation:

From the question given, we obtained the following information:

V1 = 274L

P1 = 133kPa

T1 = 316k

P2 = 98kPa

T2 = 616K

V2 =?

We can obtain the new volume by doing the following:

P1V1/T1 = P2V2/T2

133 x 274 / 316 = 98x V2 / 616

Cross multiply to express in linear form:

316 x 98 x V2 = 133 x 274 x 616

Divide both side by 316 x 98

V2 = ( 133 x 274 x 616) /316 x 98

V2 = 725L

Therefore, the new volume is 725L

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