Question

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2KClO3 → 2KCl + 3O2
How many grams of potassium chloride, KCl, are produced if 25.0g of potassium chlorate, KClO3, decompose?

 

  

15.2 g

 

  

122.6 g

 

  

30.4 g

 

  

74.6 g

 ​

Answer 1

15.2 g of KCl

First option

Step-by-step explanation:

Decomposition reaction is: 2KClO₃ → 2KCl + 3O₂

We need to convert the mass of chlorate to moles:

25 g / 122.55 g/mol = 0.204 moles

Ratio is 2:2.

Therefore 0.204 moles of chlorate will produce the same amount of chloride. We finally produce 0.204 of KCl

We convert the moles to mass → 0.204 mol . 74.55 g / 1 mol = 15.2 g of KCl