Question

Lead is obtained from the mineral galenite. The storage bin for the galenite must be able to hold 50,000 kg of galenite. If the density of galenite is 7.51 g/cm3, what volume does the storage bin need to be so as to hold the galenite

Answer 1

Answer: 6.66*10^6 cm3 or

6.66 m3

Explanation: density of galenite in g/cm3 = 7.51g/cm3 but in

Kg/cm3 = (7.51g/cm3)/1000

= 7.51*10^-3 kg/cm3

So the volume needed to hold 50000kg is = 50000/(7.51*10^-3)

V(cm3) = 6.66*10^6 cm3

Or in m3 =( 6.66*10^6)/(100^3)

V (m3)= 6.66 m3