Final answer:
The approximate maximum height of the leopard's jump is 5.0625 feet.
Step-by-step explanation:
The function h(t) = -16t^2 + 18t models the height, in feet, reached by a leopard t seconds after it jumps.
To find the approximate maximum height of the jump, we need to determine the vertex of the quadratic function.
The vertex of a quadratic function can be found using the formula x = -b/2a, where a, b, and c are the coefficients of the quadratic function.
In this case, the coefficient of t^2 is -16 and the coefficient of t is 18, so the vertex can be found using the formula t = -18/(2*-16). Solving this equation, we get t = -18/-32 = 9/16.
Substitute this value of t back into the original function to find the maximum height:
h(t) = -16(9/16)^2 + 18(9/16)
h(t) = -81/16 + 162/16 = 81/16 = 5.0625 feet.
Therefore, the approximate maximum height of the leopard's jump is 5.0625 feet.