Question

A certain kennel will house 24 dogs for 7 days. Each dog requires 10 ounces of dog food per day. If the kennel purchases dog food in cases of 30 cans each and if each can holds 8 ounces of dog food, how many cases will the kennel need to feed all of the dogs for 7 days?

Answer 1

7 cases will be needed by kennel to feed all of the dogs for 7 days.

Step-by-step explanation:

Amount of dog food required by a dog = 10 ounces

Number of dogs in kennel = 24

Number of days dog housed in kennel = 7

Total amount of dog food = T

`T=10* 24* 7 ounces=1,680 ounces`

Number of cans in single case = 30

Amount of dog food in a can = 8 ounces

Total amount of dog food in a case = 30 × 8 ounces = 240 ounces

Let the X cases of dog are needed for 7 days:

`X* 240 ounces=1,680 ounces`

`X=(1,680 ounces)/(240 ounces)=7`

7 cases will be needed by kennel to feed all of the dogs for 7 days.