Question

6.15. In an attempt to conserve water and to be awarded LEED (Leadership in Energy and Environmental Design) certification, a 20,000-liter cistern has been installed during construction of a new building. The cistern collects water from an HVAC (heating, ventilation, and air-conditioning) system designed to provide 2830 cubic meters of air per minute at 22°C and 50% relative humidity after converting it from ambient conditions (31°C, 70% relative humidity). The collected condensate serves as the source of water for lawn maintenance. Estimate (a) the rate of intake of air at ambient conditions in cubic feet per minute and (b) the hours of operation required to fill the cistern

Answer 1

Step-by-step explanation:

At temperature is
`33^(\circ) C` and relative humidity is 86% therefore, the humidity ratio is 0.0223 and the specific volume is 14.289

At temperature is
`33^(\circ) C` and Relative humidity is 40% therefore, the humidity ratio is 0.0066 and the specific volume is 13.535.

To calculate the mass of air can be calculated as follows:

`\begin{aligned}m _(1) &=( v )/( v )(1- w ) \\&=(1 * 10^(5))/(13.535)(1-0.0066) \\&=7339.49 lb / min \\v _( a ) &=( m _(1) v )/((1- w )) \\v _( a ) &=(7339.49 * 14.289)/((1-0.0223)) \\v _( a ) &=107266.0 ft ^(3) / min\end{aligned}`

Now , we going to calculate the volume,

`\begin{aligned}m _( w ) &=( v _( a ))/( v _( a )) w _( a )-( v _( i ))/( v _( i )) w _( i ) \\&=(107266.0)/(14.289) * 0.0223-(100000)/(13.535) * 0.0066 \\&=118.64 lb / min\end{aligned}`

The time which is required to fill the cistern can be calculated as follows:

`Time \(=\frac{\text { cistern volume }}{\text { removal water perminute volume }}\)`

Now, putting the value in above formula we get,

`\((\left(15 * 10^(3) L\right) *\left(0.0353147 ft ^(3) / L \right))/((118.641 b / min ) *\left((1)/(62.41 lb / ft ^(3))\right))\)\\\(=279.09\) minutes\\\(=4.65\) hours.`

Therefore, the hours required to fill the cistern is 4.65 hours.