Answer:
The probability that a person did not attend college if the person is not currently employed is 0.5602.
Explanation:
Denote the events as follows:
X = a person attended college
Y = a person is employed.
Given:
![P(X)=0.59\\P(Y|X)=0.94\\P(Y|X^(c))=0.89](https://img.qammunity.org/2021/formulas/mathematics/college/7gdd8lqbib11q3v7ervmkwvl3qw97i8jqs.png)
Compute the value of
as follows:
![P(Y^(c)|X^(c))=1-P(Y|X^(c)) = 1 - 0.89=0.11](https://img.qammunity.org/2021/formulas/mathematics/college/iwgne6zsalpxw4rd7zd4d6gkea6x0vkfr9.png)
Compute the probability of a person being employed as follows:
![P(Y)=P(Y|X)P(X)+P(Y|X^(c))P(X^(c))\\=(0.94*0.59)+(0.89*(1-0.59))\\=0.5546+0.3649\\=0.9195](https://img.qammunity.org/2021/formulas/mathematics/college/ofxp8xua9utzgg1rlhvo0yb6cscmmt7fc6.png)
Then the value a person being not employed is:
![P(Y^(c))=1-P(Y)=1-0.9195=0.0805](https://img.qammunity.org/2021/formulas/mathematics/college/qhx2qcp6e1w60wvlz8hj0x5unjfl0iew7f.png)
Compute the value of
as follows:
![P(X^(c)|Y^(c))=(P(Y^(c)|X^(c))P(X^(c)))/(P(Y^(c)))=(0.11*(1-0.59))/(0.0805)=0.5602](https://img.qammunity.org/2021/formulas/mathematics/college/sf0siqbc3svsgnqwdksra4t2f6mlo950s1.png)
Thus, the probability that a person did not attend college if the person is not currently employed is 0.5602.