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A water agency stated that waterlines cannot have water flowing faster than 8 ft/s. What is the minimum standard pipe diameter that can transport 1750 gal/min without exceeding this limit?
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A water agency stated that waterlines cannot have water flowing faster than 8 ft/s. What is the minimum standard pipe diameter that can transport 1750 gal/min without exceeding this limit?

User TheDarkKnight
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1 Answer

3 votes

Answer:

The minimum standard diameter is 0.787 ft

Step-by-step explanation:

Speed = 8 ft/s

Volumetric flow rate = 1750 gal/min = 1750 gal/min × 1 ft^3/7.481 gal × 1 min/60 s = 3.899 ft^3/s

Area of pipe (A) = volumetric flow rate ÷ speed = 3.899 ft^3/s ÷ 8 ft/s = 0.487 ft^2

Diameter of pipe = sqrt(4A/π) = sqrt(4×0.487/3.142) = sqrt(0.61999) = 0.787 ft

User Eltariel
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