Answer:
The outcomes corresponding to the five smallest possible values of Y are given by this set
{(S, S, S), (F,S,S,S), (F,F,S,S,S), (S,F,S,S,S), (F,F,F,S,S,S), (F,S,F,S,S,S), (S,F,F,S,S,S), (S,S,F,S,S,S), (F,F,F,F,S,S,S), (F,F,S,F,S,S,S), (F,S,F,F,S,S,S), (F,S,S,F,S,S,S), (S,F,F,F,S,S,S), (S,F,S,F,S,S,S), (S,S,F,F,S,S,S)}
Explanation:
You need to end with 3 success (the experiment ends there). The smallest possible value Y can take is 3, and it is given by
(S, S, S)
For Y = 4 we have only 1 possibility, the first trial is a failure and the following 3 ones are success
(F, S, S, S)
For Y = 5 we have
(F, F, S, S, S) and
(S,F,S,S,S)
For Y = 6
(F, F, F, S, S, S)
(F,S,F,S,S,S)
(S,F,F,S,S,S)
(S,S,F,S,S,S)
And lastly, for Y = 7, we have
(F,F,F,F,S,S,S)
(F,F,S,F,S,S,S)
(F,S,F,F,S,S,S)
(F,S,S,F,S,S,S)
(S,F,F,F,S,S,S)
(S,F,S,F,S,S,S)
(S,S,F,F,S,S,S)
Therefore, the total amount of possible outcomes corresponding to the five smallest possible values is
{(S, S, S), (F,S,S,S), (F,F,S,S,S), (S,F,S,S,S), (F,F,F,S,S,S), (F,S,F,S,S,S), (S,F,F,S,S,S), (S,S,F,S,S,S), (F,F,F,F,S,S,S), (F,F,S,F,S,S,S), (F,S,F,F,S,S,S), (F,S,S,F,S,S,S), (S,F,F,F,S,S,S), (S,F,S,F,S,S,S), (S,S,F,F,S,S,S)}