Question

Two children stretch a jump rope between them and send wave pulses back and forth on it. The rope is 2.6 m long, its mass is 0.5 kg, and the force exerted by the children is 44 N. What is the speed of the waves on the rope

Answer 1

15.13 m/s

Step-by-step explanation:

The wave speed of the stretched rope can be calculated using the following formula

`v = \sqrt{(F_T)/(\mu)}`

where
`F_T = 44N` is the tension on the rope and
`\mu = m/L = 0.5 / 2.6 = 0.1923 kg/m` is the density of the rope per unit length

`v = \sqrt{(44)/(0.1923)} = √(228.8) = 15.13 m/s`