Answer:
Mass of fuel used=220.54 Kg
Mass of air added=2145.189 Kg
Step-by-step explanation:
Basis 100 kg mol of flue gas
flue gas :
CO2 = 12.4 kg mol
CO = 1.2 kg mol
O2 = 5.7 kg mol
N2 = 80.7 kg mol
now N2 is provided by air
so moles of air added = 80.7/0.79 = 102.15 kg mol
so mass of air added = 102.15*21 = 2145.189 kg air
now total moles of carbon = 12.4(from CO2) + 1.2 (from CO) = 13.6 kg mol
so mass of Carbon = 13.6*12 = 163.2 kg C
so mass of fuel = 163.2/0.74 = 220.54 kg