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Quadrilateral ABCD ​ is inscribed in this circle.

What is the measure of angle C?

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°




A quadrilateral inscribed in a circle. The vertices of the quadrilateral lie on the edge of the circle and are labeled as A, B, C, D. The interior angle A is labeled as left parenthesis 2 x plus 3 right parenthesis degrees. The angle B is labeled as left parenthesis 2 x minus 4 right parenthesis degrees. The angle D is labeled as left parenthesis 3 x plus 9 right parenthesis degrees.

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The measure of angle C is 107°

Step-by-step explanation:

Given that ABCD is a quadrilateral.

The vertices A, B, C, D lie on the edge of the circle.

The measure of angle A is
\angle A=(2x+3)^{\circ

The measure of angle B is
\angle B=(2x-4)^(\circ)

The measure of angle D is
\angle D=(3x+9)^(\circ)

We need to determine the measure of angle C

Since, we know that the opposite angles B and D are supplementary.

Thus, we have,


\angle B+\angle D=180^(\circ)

Substituting the values, we get,


2x-4+3x+9=180


5x+5=180


5x=175


x=35

Thus, the value of x is 35

Substituting the value of x in the measures of angles A, B and D, we get,


\angle A=(2(35)+3)^{\circ


\angle A=(70+3)^{\circ


\angle A=73^{\circ

Similarly,
\angle B=(2x-4)^(\circ)


\angle B=(2(35)-4)^(\circ)


\angle B=(70-4)^(\circ)


\angle B=66^(\circ)

For angle D, we have,


\angle D=(3(35)+9)^(\circ)


\angle D=(105+9)^(\circ)


\angle D=114^(\circ)

Now, we shall find the measure of angle C

Since, we know that all the angles in a quadrilateral add up to 360°

Thus, we have,


\angle A+\angle B+\angle C+\angle D=360^{\circ

Substituting the values of A, B and D, we get,


73^(\circ)+66^(\circ)+\angle C+114^(\circ)=360^(\circ)


253^(\circ)+\angle C=360^(\circ)


\angle C=107^(\circ)

Thus, the measure of angle C is 107°

User Ramden
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