66.5k views
9 votes
✓ 4.) A certain molecule has an energy-level diagram for its vibrational energy in

which two levels are 0.0141eV apart. Find the wavelength of the emitted
line for the molecule as it falls from one of these levels to the other. [h
6.63 x 10-34 kgm s-?, C = 3 x 108ms-1, lev = 1.602 x 10^-19j

1 Answer

11 votes

Answer:

Step-by-step explanation:

You can use
\Delta E=(\hbar c)/(\lambda) \rightarrow \lambda =(\hbar c)/(E) = (1240 eV.nm)/(0.0141 eV) \approx 87943.26 in nm.

Here the hc = 1240 eV.nm in eV and nanometer unit.

User Olha Horak
by
5.4k points