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Please help solve questions-example-1
User Christian Klauser
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2 Answers

16 votes
16 votes

Take some points

  • 2x+3y<6
  • 3y<-2x+6
  • y<-2/3x+2

As here < sign present line will be dashed and shading should be done below the line

So

  • (1,1)
  • (1,0)
  • (2,0)
  • (-1,2)

Graph attached

Please help solve questions-example-1
User JoErNanO
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2.8k points
13 votes
13 votes

Answer:

Given inequality


\sf 2x + 3y < 6

Rearrange to make y the subject


\sf \implies 2x + 3y < 6

Subtract 2x from both sides:


\sf \implies 3y < -2x + 6

Divide both sides by 3:


\sf \implies y < -\frac23x + 2

When graphing inequalities

If the inequality sign is < or > then the line of the graph should be dashed.

If the inequality sign is ≤ or ≥ then the line of the graph should be solid.

If y < (less than) then the shading is below the line.

If y > (more than) then the shading is above the line.

Therefore, as the inequality is y < the line should be dashed and the shading should be below the dashed line.

To plot the line, substitute x = 0 and x = 3 into the equation:


\sf \implies -\frac23(0) + 2=2


\sf \implies -\frac23(3) + 2=0

Therefore, plot points (0, 2) and (3, 0). Draw a dashed straight line through the points. Shade below the dashed line.

Please help solve questions-example-1
User MJLefevre
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2.7k points