Question

In the following Lewis acid-base reaction, identify the compounds as acid, base, conjugate acid, and conjugate base. Zn(OH)3-(aq) + OH-(aq) ↔ Zn(OH)42-(aq) Zn(OH)3-(aq) Answer 1 OH- Answer 2 Zn(OH)42- Answer 3

Answer 1

Acid :
`Zn(OH)_3^(-)`

Conjugate base :
`Zn(OH)_4^(2-)`

Base:
`OH^-`

Step-by-step explanation:

According to the Lewis concept :

• An acid is defined as a substance that accepts electron pairs .
• Base is defined as a substance which donates electron pairs.

According to the Bronsted-Lowry conjugate acid-base theory:

• An acid is defined as a substance which looses donates protons and thus forming conjugate base .
• A base is defined as a substance which accepts protons and thus forming conjugate acid.

Given reaction :

`Zn(OH)_3^(-)(aq) + OH^-(aq)\rightleftharpoons Zn(OH)_4^(2-)(aq)`

`Zn(OH)_3^(-)` is acting as an acid because it is accepting hydroxide ion.And after accepting hydroxide ion it forms its conjugate base that is
`Zn(OH)_4^(2-)`

Since,
`Zn(OH)_3^(-)(aq)` is acting as an acid
`OH^-` will obviously act as base.