Answer:
a) P=0.24
b) P=0.31
c) Not independent.
Explanation:
Incomplete question.
a) What is the probability that a randomly selected order will be wrapped and sent to another person?
![P(W\&SOP)=P(SOP)*P(W|SOP)=0.30*0.60=0.24](https://img.qammunity.org/2021/formulas/mathematics/college/oalkzc8jb4h9xwh9ry1ug46va0nooai20f.png)
W: wrapped
SOP: sent to other people
b) What is the probability that a randomly selected order will be gift wrapped?
![P(W)=P(SOP)*P(W|SOP)+P(SR)*P(W|SR)\\\\P(W)=0.3*0.6+0.7*0.1=0.24+0.07=0.31](https://img.qammunity.org/2021/formulas/mathematics/college/bsybp6ogcav4vj21diav9ghayd4xq69a4t.png)
SR: sent to the right person
c) Is gift wrapping independent of the destination of the gift? Justify your response statistically.
To prove that they are independent, both of the following conditions must be met:
- P(x|y) = P(x), for all values of X and Y.
- P(x ∩ y) = P(x) * P(y), for all values of X and Y.
We start for the second condition.
![P(W\cap SR)=0.1\\\\P(W)*P(SR)=0.31*0.7=0.217\\\\\\P(W\cap SR)\\eq P(W)*P(SR)](https://img.qammunity.org/2021/formulas/mathematics/college/yvw3elj4lo5x1vtc5yx9gs77157e6kc03u.png)
This condition is not met, so the two variables are not independent.