Question

What is the solution of StartRoot x + 12 EndRoot = x?

x = –3
x = 4
x = –3 or x = 4
no solution

Answer 1

C

Explanation:

Answer 2

x = 4 or x = -3

Explanation:

`√(x+12)=x`

Take square both the sides,

`(√(x+12))^(2)=x^(2)\\\\x+12=x^(2)`

x² - x - 12 = 0

x² - 4x + 3x - 3*4 =0

x*(x - 4) + 3*(x - 4)= 0

(x- 4 )(x+3) =0

x -4 =0 or x + 3 = 0

x = 4 or x = -3