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PLZ HELP What is the solution to the system of equations below?

y = one-half x + 6 and y = negative three-fourths x minus 4
A. (–8, 2)
B. (–8, –1)
C. (8, 10)
D. (8, –10)

User Jericon
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2 Answers

7 votes

Answer:

A. (–8, 2)

Explanation:

User Jeff Sheldon
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4 votes

Answer:

A. (–8, 2)

Explanation:

The given system is


y=(1)/(2)x+6\\ y=-(3)/(4)x-4

Let us equate both of them to get:


(1)/(2)x+6=-(3)/(4)x-4

Multiply through by 4 to get:


4*(1)/(2)x+4*6=4*-(3)/(4)x-4*4

Simplify:


2x+24=-3x-16

Group similar terms:


2x+3x=-16-24\\5x=-40\\x=-8

Put x=-8 in the first equation:


y=(1)/(2)(-8)+6=-4+6=2

The correct answer is A

User Sweets
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