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for question 1-3, consider the following code what is output if the user types in 9? click all that apply A, B, C, D click all that apply QUESTION #1 x = ( input a number: ")) if (x != 8): print ("A") if (x >= 10): print ("8") if (x < 10): print ("C") if (x % 2 = = 1)): print ("D") QUESTION #2 what is output if the user types in 8? click all that apply A , B, C, D QUESTION #3 what is output if the user types in 13? click all that apply A,B,C,D QUESTION #4 the following code is intended to test if x is NOT less than 17. fill in the correct symbol if ( x ______ 17): PLEASE HELP ​

2 Answers

4 votes

Final answer:

When the user inputs 9, the output is 'A', 'C', and 'D'. For 8, the output is 'C' only. For 13, the output is 'A', and 'D', with the assumption 'B' should be printed based on the pattern. To test if x is not less than 17, the symbol '>=' is used.

Step-by-step explanation:

Let's address each question step by step based on the provided pseudo-code.

Question #1

For the input of 9:

  • if (x != 8): This condition is true because 9 is not equal to 8, so 'A' is printed.
  • if (x >= 10): This condition is false because 9 is not greater than or equal to 10, so 'B' is not printed.
  • if (x < 10): This condition is true because 9 is less than 10, so 'C' is printed.
  • if (x % 2 == 1): This condition is true because 9 modulo 2 equals 1, so 'D' is printed.

Question #2

For the input of 8:

  • if (x != 8): This condition is false because 8 is equal to 8, so 'A' is not printed.
  • if (x >= 10): This condition is false because 8 is not greater than or equal to 10, so 'B' is not printed.
  • if (x < 10): This condition is true because 8 is less than 10, so 'C' is printed.
  • if (x % 2 == 1): This condition is false because 8 modulo 2 equals 0, so 'D' is not printed.

Question #3

For the input of 13:

  • if (x != 8): This condition is true because 13 is not equal to 8, so 'A' is printed.
  • if (x >= 10): This condition is true because 13 is greater than 10, so 'B' is not printed as it seems to be a typo since it doesn't match the pattern. Presuming that 'B' was actually intended to be 'print ("B")', the correct answer would be that 'B' is printed.
  • if (x < 10): This condition is false because 13 is not less than 10, so 'C' is not printed.
  • if (x % 2 == 1): This condition is true because 13 modulo 2 equals 1, so 'D' is printed.

Question #4

To test if x is NOT less than 17, the correct symbol to fill in would be '>=', representing 'greater than or equal to'. The code should be written as:

if (x >= 17):
User Simon Kocurek
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Final answer:

The outputs after inputting 9 are A, C, and D. For the input of 8, no letter is specified, though C would be logically expected. Inputting 13 results in A, (presumed B), and D. The symbol to check if x is not less than 17 is >=.

Step-by-step explanation:

When analyzing the provided code, it appears it contains several conditions that check the input number against certain criteria and prints a corresponding letter based on the result.

Question #1: Output for number 9

If the user inputs 9, the conditions will result in the following outputs:

A is printed because 9 is not equal to 8.

C is printed because 9 is less than 10.

D is printed because 9 is an odd number (9 % 2 equals 1).

Question #2: Output for number 8

If the user inputs the number 8, only one condition is satisfied:

A is not printed because 8 is equal to 8, so the condition fails.

B and D conditions depend on variables or values that are not defined in the provided context.

C is printed because 8 is less than 10.

Question #3: Output for number 13

For the number 13, the following outcomes will occur:

A is printed because 13 is not equal to 8.

B is printed because 13 is greater than or equal to 10.

D is printed because 13 is an odd number (13 % 2 equals 1).

Question #4: Correct Symbol for Testing if x is NOT less than 17

The correct symbol to complete the condition to test if x is not less than 17 is \u0027>=\u0027.