Question

The concentration of Si in an Fe-Si alloy is 0.25 wt%. What is the concentration in kilograms of Si per cubic meter of alloy?

Answer 1

Answer : The concentration of Si in kilograms is,
`19.55kg/m^3`

Explanation :

As we are given that, the concentration of Si in an Fe-Si alloy is 0.25 wt% that means:

Weight of Si = 0.25 g = 0.00025 kg

Weight of Fe = 100 - 0.25 = 99.75 g = 0.09975 kg

Density of Si =
`2.32g/cm^3=2.32* 10^6g/m^3`

Density of Fe =
`7.87g/cm^3=7.87* 10^6g/m^3`

Now we have to calculate the concentration in kilograms of Si per cubic meter of alloy.

Concentration of Si in kilograms =
`\frac{\text{Weight of Si in 100 g of alloy}}{\text{Volume of 100 g of alloy}}`

Concentration of Si in kilograms =
`\frac{\text{Weight of Si in 100 g of alloy}}{\frac{\text{Wight of Fe}}{\text{Density of Fe}}+\frac{\text{Wight of Si}}{\text{Density of Si}}}`

Now put all the given values in this expression, we get:

Concentration of Si in kilograms =
`(0.00025kg)/((99.75g)/(7.87* 10^6g/m^3)+(0.25g)/(2.23* 10^6g/m^3))`

Concentration of Si in kilograms =
`19.55kg/m^3`

Thus, the concentration of Si in kilograms is,
`19.55kg/m^3`