Question

At a certain temperature, the equilibrium constant, K c , for this reaction is 53.3. H 2 ( g ) + I 2 ( g ) − ⇀ ↽ − 2 HI ( g ) K c = 53.3 At this temperature, 0.800 mol H 2 and 0.800 mol I 2 were placed in a 1.00 L container to react. What concentration of HI is present at equilibrium?

Answer 1

The equilibrium concentrations of H₂, I₂, and HI are approximately 1.00 mole/L, 2.00 moles/L, and 0.199 moles/L respectively.

Step-by-step explanation:

To find the equilibrium concentrations of H₂, I₂, and HI in moles/L, we need to use the stoichiometry of the reaction and the given equilibrium constant. The stoichiometry tells us that for every 1 mole of H₂ and I₂ that react, 2 moles of HI are produced. Let's represent the equilibrium concentrations of H₂, I₂, and HI as [H₂], [I₂], and [HI] respectively.

Using the given equilibrium constant, K = 50.5, and the initial concentrations of 1.00 mole of H₂ and 2.00 moles of I₂ in a 1.00-L flask, we can set up an expression for the equilibrium concentrations:

[H₂][I₂] / [HI]² = K

Plugging in the given values:

(1.00)(2.00) / [HI]² = 50.5

[HI]² = (1.00)(2.00) / 50.5

[HI]² = 0.0396

[HI] = √(0.0396) ≈ 0.199 moles/L

Therefore, at equilibrium, the concentrations are approximately:

[H₂] ≈ 1.00 mole/L, [I₂] ≈ 2.00 moles/L, [HI] ≈ 0.199 moles/L

Answer 2

Answer: Concentration of HI is present at equilibrium is 1.26 M

Step-by-step explanation:

Moles of
`H_2` = 0.800 mole

Moles of
`I_2` = 0.800 mole

Volume of solution = 1.00 L

Initial concentration of
`H_2` = 0.800 M

Initial concentration of
`I_2` = 0.800 M

The given balanced equilibrium reaction is,

`H_2(g)+I_2(g)\rightleftharpoons 2Hl(g)`

Initial conc. 0.800 0.800 0

At eqm. conc. (0.800-x) M (0.800-x) M (2x) M

The expression for equilibrium constant for this reaction will be,

`K_c=([HI]^2)/([H_2]* [l_2])`

Now put all the given values in this expression, we get :

`53.3=((2x)^2)/((0.800-x)^2)`

By solving the term 'x', we get :

x = 0.63

Concentration of
`HI` at equilibrium = 2 x =
`2* 0.63=1.26`

Concentration of HI is present at equilibrium is 1.26 M