Question

For the reaction: 3 KClO3 to 3 KCL + 4O2, How many miles of potassium chloride are produced from 9.3 grams of potassium chloride?

Answer 1

5.7 g of KCl is produced.

Step-by-step explanation:

First we have to write the balanced equation as,

`2 K C l O_(3) \rightarrow 2 K C l+3 O_(2) \uparrow`

Then we have to find the moles of potassium chlorate as,

`Moles of $K C l O_(3)=9.3 g$ of $K C l O_(3) * \frac{1 \text { mol of } K C l O_(3)}{122.55 g K C l O_(3)}=0.076$ moles`

Then we have to find the moles of KCl as,

`Moles of $\mathrm{KCl}=0.076$ moles of $\mathrm{KClO}_(3) * \frac{2 \text { mol of } \mathrm{KCl}}{2 \text { mol } \mathrm{KClo}_(3)}=0.076$ moles`

From the moles of KCl, we have to find the mass using its molar mass by multiplying them as,

`\text { Mass of } \mathrm{KCl}=0.076 \text { mol } * 74.55 \frac{g}{\mathrm{mol}}=5.7 \mathrm{g} \text { of } \mathrm{KCl}`