Question

- passing through (3,-6), (-6, -3)​

Answer 1

`y=-(1)/(3)x-5`

Explanation:

We want to find the equation of the line passing through (3,-6), (-6, -3)​.

Write the formula for slope:

`m=(y_2-y_1)/(x_2-x_1)`

Substitute
`(x_1=3,y_1=-6),(x-2=-6,y_2=-3)`

`m=(-3--6)/(-6-3)\\ m=(3)/(-9)\\m=-(1)/(3)`

Use the formula
`y=m(x-x_1)+y_1` to find the equation.

Substitute the point and slope to get:

`y=-(1)/(3)(x-3)+-6`

Simplify:

`y=-(1)/(3)x+1+-6`

`y=-(1)/(3)x-5`