Question

The electric field intensity at a particular location surrounding a Van de Graaff generator is 4.5x103 N/C. Determine the magnitude of the force that this field would exert upon ...

Answer 1

Step-by-step explanation:

Electric field, E = 4.5 x 10^3 N/C

charge on electron, e = 1.6 x 10^-19 C

The relation between the force and the electric field is given by

F = q E

F = 1.6 x 10^-19 x 4.5 x 10^3

F = 7.2 x 10^-16 N

Answer 2

The magnitude of the force is
`7.2*10^(-16)\ N`

Step-by-step explanation:

Given that,

Electric field intensity
`E= 4.5*10^3`

Suppose, The electron when positioned at this location

We need to calculate the magnitude of the force

Using formula of electric field

`E = (F)/(q)`

`F = Eq`

Where, E = electric field

q = charge of electron

Put the value into the formula

`F=4.5*10^3*1.6*10^(-19)`

`F=7.2*10^(-16)\ N`

Hence, The magnitude of the force is
`7.2*10^(-16)\ N`