Question

A single loop of wire with an area of 0.0800 m^2 is placed in a uniform magnetic field that has an initial value of 1.50 T. The field is perpendicular to the plane of the loop, and its strength is decreasing at a constant rate of 0.400 T/s. The loop has a resistance of 0.400. What current is induced in this loop?

Answer 1

0.0800A

Step-by-step explanation:

Given the Area as
`A=0.0800m^2` and that the wire is perpendicularly placed in a magnetic field that has an initial value
`B=1.50T` and a decreasing constant
`|dB/dt|=0.400T/s`, the magnitude of the induce emf is :

`|\varepsilon|=|{(d\Phi_B)/(dt)}| \ \ \ \Phi_B=BAcos(\phi), \phi=0`

`|\varepsilon|=A(dB)/(dt)\\\\|\varepsilon|=(0.0800m^2)(0.400T/s)=0.0320V`

To find the current induced in the loop of resistance 0.400 ohms:

`I=(\varepsilon)/(R)\\\\=0.0320V/0.400\Omega\\\\I=0.0800A`

The induced current in the loop is 0.0800A