Question

A 3.04 kg particle is located on the x-axis at xm = −8 m, and a 5.61 kg particle is on the x-axis at xM = 3.56 m. Find the coordinate of the center of mass of this two-particle system. Answer in units of m.

Answer 1

center of mass = −0.50 m

Step-by-step explanation:

given data

mass m1 = 3.04 kg

distance xm = -8 m

mass m2 = 5.61 kg

distance xM = 3.56 m

solution

we get here center of mass for n mass of system that is express as

center of mass =
`(m_1x_1+m_2x_2......m_nx_n)/(m_1+m_2...m_n)` ......................1

but we have only 2 particle system so we will get

center of mass =
`(m1 * xm+m2 * xM)/(m1+m2)` .................2

put here value and we will get

center of mass =
`(3.04 * (-8 )+5.61 * 3.56)/(3.04 + 5.61)`

solve it we will get

center of mass = −0.50 m