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Three individuals stand with all of their weight on the heel of one foot: a man of weight 600 N and a heel area of 100 cm 2, a child of weight 200 N and a heel area of 25 cm 2, and woman of weight 450 N and a heel area of 2 cm 2. The one exerting the least pressure on the ground is

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Answer:

The man exerts the lease pressure on ground

Step-by-step explanation:

Pressure is the force (F) applied per unit area (A).


P = (F)/(A)

Let us find out the pressure for each individual.

1. For the man with weight (F) = 600N and heel area (A) = 100cm², the pressure on the ground (
P_(m)) is,


P_(m) = (F)/(A)


P_(m) = (600)/(100) = 6 N/cm^(2)

2. For the child with weight (F) = 200N and heel area (A) = 25cm², the pressure on the ground (
P_(c)) is,


P_(c) = (200)/(25) = 8 N/cm^(2)

3. For the woman with weight (F) =450N and heel area (A) = 2cm², the pressure on the ground (P_{w}) is,


P_(w) = (450)/(2) = 225 N/cm^(2)

Thus the man is exerting least pressure on the ground that is 6 N/cm².

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