Question

You are using a standardized 0.1250 M solution of sodium hydroxide to determine the concentration of sulfuric acid. After pipetting 10.00 mL of the H2SO4 into your flask you find that you use 19.22 mL of your NaOH solution to reach the endpoint. No, wait... I mean What is the concentration of the sulfuric acid? H2SO4 + 2NaOH ---> Na2SO4 + 2HOH

Answer 1

Answer: Thus the concentration of the sulfuric acid is 0.1201 M

Step-by-step explanation:

`H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O`

To calculate the concentration of acid, we use the equation given by neutralization reaction:

`n_1M_1V_1=n_2M_2V_2`

where,

`n_1,M_1\text{ and }V_1` are the n-factor, molarity and volume of acid which is
`H_2SO_4`

`n_2,M_2\text{ and }V_2` are the n-factor, molarity and volume of base which is NaOH.

We are given:

`n_1=2\\M_1=?\\V_1=10.00mL\\n_2=1\\M_2=0.1250M\\V_2=19.22mL`

Putting values in above equation, we get:

`2* M_1* 10.00=1* 0.1250* 19.22\\\\M_1=0.1201M`

Thus the concentration of the sulfuric acid is 0.1201