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How many grams of lithium nitride needs to react with excess water at stp to produce 15.0 l of ammonia

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Final answer:

To determine the limiting reactant, compare the number of moles of lithium nitride that can be formed from each reactant.

Step-by-step explanation:

The question mentions the reaction:



Li + N2 -> Li3N



To determine the limiting reactant, we need to compare the number of moles of lithium nitride that can be formed from each reactant. To do this, we need to convert the mass of lithium and nitrogen to moles:



Lithium: 1.50 g ÷ molar mass of lithium = x moles



Nitrogen: 1.50 g ÷ molar mass of nitrogen = y moles



Whichever reactant produces the smaller number of moles of lithium nitride is the limiting reactant.

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