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What is the derivative of
f(x)=(In(x))/(x)~?

User Pallie
by
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1 Answer

2 votes

Answer and Step-by-step explanation:


Greetings!


Let's~answer~your~question!


By~quotient~rule,


y'=((1)/(x)*x~-~In~x*1 )/(x^2) =(1-In~x)/(x^2)


This~ problem ~can ~also ~be ~solved ~by~ the ~Product~ Rule:


y'=f'(x)~g(x)+f(x)~g(x)


The~ original~ function ~can~ also~be~ rewritten~ using ~negative~ exponents:


f(x)=(In(x))/(x)=In(x)*x^-^1


f'(x)=(1)/(x) *x^-^1+ln(x)*-1x^-^2


f'(x)=(1)/(x)*(1)/(x)+In(x)*-(1)/(x^2)


f'(x)=(1)/(x^2)-(In(x))/(x^2)


f'(x)=(1-In(x))/(x^2)

User FTW
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