Question

In the first 11.0 s s of the reaction, 1.6×10−2 mol mol of O2O2 is produced in a reaction vessel with a volume of 0.500 L L . What is the average rate of the reaction over this time interval?

Answer 1

The answer to the question is;

The average rate of the reaction over the 11 seconds time interval is

1.455×10⁻³ mol/s.

Step-by-step explanation:

To solve the question, we note that

Quantity of O₂ produced = 1.6×10⁻² mol

Reaction time = 11 seconds

Volume of reaction = 0.5 L

The rate of a chemical reaction is given by

Average rate of reaction =
`(d[O_2])/(dt)`

Average rate of production of O₂ k =
`(1.6*10^(-2))/(11)` = 1.455×10⁻³ mol/second.

Answer 2

1.4546 mol/sec

Step-by-step explanation:

Reaction rate is defined as the number of moles of product formed per unit time.

Therefore,

Reaction Rate = amount of O2 produce / time taken to produce it

since in the reaction above the time in question is 11 seconds, and the amount in mole of O2 formed is 1.6×10−2;

Reaction Rate = 1.6×10−2/ 11

= 1.4546 mol/sec

Reactant concentration, the physical state of the reactants, and surface area, temperature, and the presence of a catalyst are the four main factors that affect reaction rate.