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A long rod of 60-mm diameter and thermophysical properties rho=8000 kg/m^3, c=500J/kgK, and k=50 W/mK is initally at a uniform temperature in a forced convection furnace maintained at 750K. The convection coeffiecent is estimated to be 1000 W/m^2K.

What is the centerline temperature of the rod when the surface temperature is 550K?

1 Answer

3 votes

Answer:

Tc = 424.85 K

Step-by-step explanation:

Given that,


D = 60 mm = 0.06 m


\rho = 8000 kg/m^3


k = 50 w/m . kc = 500 j/kg.k


h_(\infty) = 1000 w/m^2t_(\infity) = 750 kt_w = 500 K


surface area = As = \pi dL \\(As)/(L) = \pi D = \pi \timeS 0.06

HEAT FLOW Q is


Q = h_(\infty) As (T_[\infty} - Tw) = 1000 \pi* 0.06 (750-500)

= 47123.88 w per unit length of rod

volumetric heat rate


q = (Q)/(LAs)


= (47123.88)/((\pi)/(4) D^2 * 1)


q = 1.66* 10^(7) w/m^3


Tc = (- qR^2)/(4K) + Tw


= ( - 1.67* 10^7 * ((0.06)/(2))^2)/(4* 50) + 500

= 424.85 K

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