The needed probability is 0.4.
Explanation:
Here, given that two fair dices are rolled.
The sum of both the numbers on the dice = 6
Also, number on one of the dice = 4
Let us write the given possibilities.
The outcomes when ("one of the dice shows 4") are: (2, 4) and (4, 2)
The outcomes when ("given that the sum of the dice is 6") are:
(1, 5) , (2, 4) , (3, 3), (4, 2) and (5, 1)
As we can see from the above information, that the total outcomes when the sum of digits is 6 is 5.
Also, the favorable outcomes = 2
So, there are total 2 out of 5 events which are desirable to given condition.
So, the required probability =
![\frac{\textrm{The number of desirable events}}{\textrm{Total number of events}} = (2)/(5) = 0.4](https://img.qammunity.org/2021/formulas/mathematics/high-school/7comiv8ma7u6l1w3nmw8ei6rgs19rcpowh.png)
Hence, the needed probability is 0.4.