Question

a 25.0mL sample of ammonium nitrate solution produces a 0.186 M solution when diluted with 50.0mL of water. what is the molarity of the stock solution

Answer 1

C₁ = 0.558 M

Step-by-step explanation:

Given data:

Volume of concentrated solution = V₁ = 25 mL

Molarity of concentrated solution =C₁ = ?

Volume of diluted solution = V₂ = 50mL + 25 mL = 75 mL

Molarity of diluted solution = C₂ = 0.186 M

Solution:

Formula:

C₁V₁ = C₂V₂

Volume of concentrated solution = V₁

Molarity of concentrated solution =C₁

Volume of diluted solution = V₂

Molarity of diluted solution = C₂

Now we will put the values in formula:

C₁V₁ = C₂V₂

C₁ × 25 mL = 0.186 M ×75 mL

C₁ × 25 mL = 13.95 M.mL

C₁ = 13.95 M.mL/25 mL

C₁ = 0.558 M