91.8k views
1 vote
Please help :) I have no clue & math isn’t my strong subject.

Please help :) I have no clue & math isn’t my strong subject.-example-1
User Banjollity
by
8.1k points

1 Answer

6 votes

Equation of a line that is perpendicular to given line is
y=(-7)/(4) x+(7)/(4).

Equation of a line that is parallel to given line is
y=(4)/(7) x-(69)/(7).

Solution:

Given line
y=(4)/(7) x+4.

Slope of this line,
m_1 =
(4)/(7)


$\text{Slope of perpendicular line} = \frac{-1}{\text{Slope of the given line} }


$m_2=(-1)/(m_1)


$=(-1)/((4)/(7) )

Slope of perpendicular line,
m_2=(-7)/(4)

Passes through the point (–7, 5). Here
x_1=-7, y_1=5.

Point-slope formula:


y-y_1=m(x-x_1)


$y-(-7)=(-7)/(4) (x-5)


$y+7=(-7)/(4) x+(35)/(4)

Subtract 7 from both sides, we get


$y=(-7)/(4) x+(7)/(4)

Equation of a line that is perpendicular to given line is
y=(-7)/(4) x+(7)/(4).

To find the parallel line:

Slopes of parallel lines are equal.


m_1=m_3


$m_3=(4)/(7)

Passes through the point (–7, 5). Here
x_1=-7, y_1=5.

Point-slope formula:


$y-(-7)=(4)/(7) (x-5)


$y+7=(4)/(7) x-(20)/(7)

Subtract 7 from both sides,


$y=(4)/(7) x-(69)/(7)

Equation of a line that is parallel to given line is
y=(4)/(7) x-(69)/(7).

User Lakshman
by
8.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories