Question

A straight wire carries a current of 8.00 A toward the top of the page.

What are the magnitude and direction of the magnetic field at point P, which is 8.00 cm to the right of the wire?

Answer 1

The magnetic field is
`2* 10^(-5)\ T`.

Step-by-step explanation:

Given that,

Current carried in the wire, I = 8 A toward the top of the page.

We need to find the magnetic field at point P, which is 8.00 cm to the right of the wire. The magnetic field is given by :

`B=(\mu_o I)/(2\pi r)\\\\B=(4\pi * 10^(-7)* 8)/(2\pi * 0.08)\\\\B=2* 10^(-5)\ T`

So, the magnetic field is
`2* 10^(-5)\ T`. Hence, this is the required solution.