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Assume that blood pressure readings are normally distributed with a mean of 124124 and a standard deviation of 9.69.6. If 144144 people are randomly​ selected, find the probability that their mean blood pressure will be less than 126126.

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Answer:

Probability that their mean blood pressure will be less than 126 is 0.9938.

Explanation:

We are given that blood pressure readings are normally distributed with a mean of 124 and a standard deviation of 9.6. Also, 144 people are randomly​ selected.

Let
\bar X = mean blood pressure

So,
\bar X ~ N(
\mu= 124, s.d. = (9.6)/(√(144) ))

The z score probability distribution for sample mean is given by;

Z =
(\bar X-\mu)/((\sigma)/(√(n) ) ) ~ N(0,1)

where,
\mu = population mean


\sigma = population standard deviation

n = sample size = 144

So, probability that their mean blood pressure will be less than 126 is given by = P(
\bar X < 126)

P(
\bar X < 126) = P(
(\bar X-\mu)/((\sigma)/(√(n) ) ) <
(126-124)/((9.6)/(√(144) ) ) ) = P(Z < 2.50) = 0.9938 {using z table}

Therefore, probability that their mean blood pressure will be less than 126 is 0.9938 .

User Sandeep Chikhale
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