Answer: a) -43.4 Hz, b) -7.90m
Explanation: This is a question under Doppler effect.
The mathematical equation of doppler effect is given as
fo = (v + vo)/(v -vs) × fs
Where fo = frequency perceived by observer = ?
v = speed of sound in air = 343m/s
vo = velocity of obseerver relative to the source = 0 (since he is not moving)
vs = velocity of source relative to the observer = 22.8 m/s
fs = frequency of sound produced by source = 325 Hz
For the condition where the train is approaching the observer, velocity of source relative to the observer (vs) is positive, hence vs = 22.8 m/s
fo = (343+0)/(343 -22.8) × 325
fo = (343/ 320.2) × 325
fo = 1.071 × 325 = 348.14 Hz.
For the condition where the train is moving away from the observer, velocity of source relative to the observer (vs) is negative, hence vs = -22.8 m/s
fo = (343+0)/(343 -(-22.8)) × 325
fo = (343/ 343 +22.8) × 325
fo = (343/365.8) × 325
fo = 0.9377 × 325 = 304.74 Hz
Change in frequency as the train moves from approaching to receeding is = 304.74 - 348.14 = -43.4 Hz.
But v = speed of sound in air = 343 m/s.
We can get the change in wavelength by using the formulae
V = fλ
Where v = speed of sound in air = 343 m/s
f = change in frequency = -43.4 Hz
λ = change in wavelength = ?
343 = (-43.4) × λ
λ = 343 / -43.4
λ = -7.90 m
The negative sign beside the wavelength shows decrease