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Mr. Smith invests a certain amount of money at 8% and twice as much at 5%. If his annual income from the two investments is $720, how much does he have invested at 5%? (in $)

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The amount invested by Mr.Smith in 5% is $240 .

Explanation:

We have , Mr. Smith invests a certain amount of money at 8% and twice as much at 5%. If his annual income from the two investments is $720 . Let us suppose that Mr.Smith invest $x so :

Amount of money invested in 5% is
(5x)/(100) . And, amount of money invested in 8% is twice that of 5% i.e.
((2)5x)/(100) = (10x)/(100) .

Now, total investment is $720 so,


(5x)/(100) +(
((2)5x)/(100) = (10x)/(100) ) = $720


(5x)/(100) + (10x)/(100) = 720


(15x)/(100) = 720


(100(720))/(15) = x


x = 4800

The amount invested by Mr.Smith in 5% is
(5x)/(100) i.e.
(5(4800))/(100) = 240. ∴ The amount invested by Mr.Smith in 5% is $240 .

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