Question

Enter the net ionic equation for the reaction between HF (a weak acid) and KOH.

Express your answer as a net ionic equation. Identify all of the phases in your answer.

Answer 1

The net ionic equation for the reaction between hydrofluoric acid (HF), a weak acid, and potassium hydroxide (KOH), a strong base, is HF (aq) + OH- (aq) → F- (aq) + H2O (l). In this reaction, hydroxide ions react with hydrofluoric acid to form water and fluoride ions.

Step-by-step explanation:

The reaction between hydrofluoric acid (HF), which is a weak acid, and potassium hydroxide (KOH), which is a strong base, can be represented by the following net ionic equation:

HF (aq) + OH- (aq) → F- (aq) + H2O (l)

In this reaction, HF is a weak acid and does not completely dissociate in water. Therefore, it is represented as HF (aq) in the net ionic equation. Potassium hydroxide, KOH, is a strong base and dissociates completely into K+ (aq) and OH- (aq) ions in an aqueous solution. The hydroxide ions (OH-) from KOH react with HF to form water (H2O) and fluoride ions (F-), which are soluble in water. Potassium ions (K+) are spectator ions and do not participate in the net ionic equation.

Answer 2

Step-by-step explanation:

Since, HF is a weak acid so it will partially dissociate into the solution. Whereas KOH is a strong base therefore, it will completely dissociate into its constituent ions as
`K^(+)` and
`OH^(-)`.

The chemical equation for this reaction is as follows.

`HF + K^(+) + OH^(-) \rightarrow K^(+) + F^(+) + H_(2)O`

On cancelling the spectator ions from both the sides in the above equation we will get the net ionic equation as follows.

`HF + OH^(-) \rightarrow F^(-) + H_(2)O`