Question

If 18.9 J of heat was gained when 2.6 g of O subscript 2 was heated, what was the temperature change that occurred? (The specific heat of O subscript 2 is 0.954 J/g °C)

Answer 1

Answer: The temperature change that occurred is 7.62°C

Step-by-step explanation:

The equation used to calculate heat absorbed follows:

`Q=m* c* \Delta T`

where,

Q = heat absorbed = 18.9 J

m = mass of oxygen gas = 2.6 g

c = specific heat of oxygen gas = 0.954 J/g°C

`\Delta T` = change in temperature = ?

Putting values in above equation, we get:

`18.9J=2.6g* 0.954 J/g^oC* \Delta T\\\\\Delta T=(18.9)/(2.6* 0.954)=7.62^oC`

Hence, the temperature change that occurred is 7.62°C