Answer:
15.7 kg of CO₂ are added to the atmosphere per 5.1 kg of octane burned
Step-by-step explanation:
These are always the reactants in a combustion:
- O₂
- C₈H₁₈ (octane, in this case)
These are always the products in the combustion
- CO₂ and H₂O
The balanced reaction is: 2C₈H₁₈ + 25O₂ → 16CO₂ + 18H₂O
We assume the oxygen in excess, so the limting reactant is the octane.
We convert the mass to moles but first we need to convert the kg to g
5.1 kg . 1000 g / 1kg = 5100 g → 5100 g . 1 mol / 114g = 44.7 moles of octane
By stoichiometry, ratio is 2:16. Let's make a rule of three:
2 moles of octane produce 16 moles of dioxide
Therefore 44.7 moles of octane must produce (44.7 . 16) / 2 = 358 moles of CO₂
We convert the moles to mass (g), and finally we convert from g to kg
358 mol . 44g / 1mol = 15747 g → 15747 g. 1 kg / 1000g = 15.7 kg of CO₂