Question

A woman bought some large frames for ​$18 each and some small frames for ​$8 each at a closeout sale. If she bought 21 frames for ​$​248, find how many of each type she bought.

Answer 1

8 large frames and 13 small frames

Explanation:

Given:
$18 each = large frames

$8 each = small frames

To Find:

⇒ Bought 21 frames for ​$​248, find how many of each type she bought

Solve:

1 Large frame costs = 18 $

Therefore, x large frames costs = 18x $

{where x is the number of large frames she bought}

1 Small frame costs = 8 $

Therefore, x Small frames costs = 8y $

{where y is the number of small frames she bought}

By the given condition :

18x + 8y = 248 {equation 1}

x + y = 21 {equation 2}

Solve these equations simultaneously, from second equation we get :

x = 21- y

18⋅(21−y)+8y= 248

378 - 18y+8y = 248

-10y = -130

y = 13

Put y = 13 in eq x = 21- y

x = 21 - y

x = 21 - 13

x = 8

So the woman bought 8 large frames and 13 small frames.

~lenvy~