Question

Carbon tetrachloride reacts at high temperatures with oxygen to produce two toxic gases, phosgene and chlorine. CCl4(g) + (1/2)O2(g) <====> COCl2(g) + Cl2(g), with Kc = 4.4 x 109 at 1,000 K

Answer 1

The question is incomplete, here is the complete question:

Carbon tetrachloride reacts at high temperatures with oxygen to produce two toxic gases, phosgene and chlorine.

`CCl_4(g)+(1)/(2)O_2(g)\rightleftharpoons COCl_2(g)+Cl_2(g);K_c=4.4* 10^9` at 1,000 K

Calculate Kc for the reaction
`2CCl_4(g)+O_2(g)\rightleftharpoons 2COCl_2(g)+2Cl_2(g)`

Answer: The value of
`K_c'` for the final reaction is
`1.936* 10^(19)`

Step-by-step explanation:

The given chemical equations follows:

`CCl_4(g)+(1)/(2)O_2(g)\rightleftharpoons COCl_2(g)+Cl_2(g);K_c`

We need to calculate the equilibrium constant for the equation, which is:

`2CCl_4(g)+O_2(g)\rightleftharpoons 2COCl_2(g)+2Cl_2(g)`

As, the final reaction is the twice of the initial equation. So, the equilibrium constant for the final reaction will be the square of the initial equilibrium constant.

The value of equilibrium constant for net reaction is:

`K_c'=(K_c)^2`

We are given:

`K_c=4.4* 10^9`

Putting values in above equation, we get:

`K_c'=(4.4* 10^9)^2=1.936* 10^(19)`

Hence, the value of
`K_c'` for the final reaction is
`1.936* 10^(19)`