Question

f an arrow is shot upward on the moon with velocity of 35 m/s, its height (in meters) after t seconds is given by h(t)=35t−0.83t 2. (a) Find the velocity of the arrow after 3 seconds.

Answer 1

The velocity of the arrow after 3 seconds is 30.02 m/s.

Step-by-step explanation:

It is given that,

An arrow is shot upward on the moon with velocity of 35 m/s, its height after t seconds is given by the equation:

`h(t)=35t-0.83t^2`

We know that the rate of change of displacement is equal to the velocity of an object.

`v(t)=(dh(t))/(dt)\\\\v(t)=(d(35t-0.83t^2))/(dt)\\\\v(t)=35-1.66t`

Velocity of the arrow after 3 seconds will be :

`v(t)=35-1.66t\\\\v(t)=35-1.66(3)\\\\v(t)=30.02\ m/s`

So, the velocity of the arrow after 3 seconds is 30.02 m/s. Hence, this is the required solution.